a triangular course for a canoe race is marked with buoys. the first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi. how long is the race? (the numbers are fractions)
Accepted Solution
A:
Answer:1 1/5 miStep-by-step explanation:We need to add the three legs together3/10 + 1/2 + 2/5The common denominator is 103/10 Β =3/101/2 *5/5 = 5/102/5 *2/2 =4/103/10 + 5/10+4/10 = 12/1010/10 = 10/10+2/10 = 1+2/10 Β = 1 1/5 mi